Correct Answer - Option 5 : Relation can't be established or x = y
I. x2 – 13x + 40 = 0
⇒ x2 – 8x – 5x + 40= 0
⇒ x(x – 8) – 5(x – 8) = 0
⇒ (x – 8)(x – 5) = 0
⇒ x = 5 or 8
II. y2 – 11y + 24 = 0
⇒ y2 – 3y – 8y + 24 = 0
⇒ y(y – 3) – 8 (y – 3) = 0
⇒ (y – 3)(y – 8) = 0
⇒ y = 3 or 8
x |
sign |
y |
5 |
> |
3 |
5 |
< |
8 |
8 |
> |
3 |
8 |
= |
8 |
∴ Relation can't be established or x = y