Correct Answer - Option 4 : 6000
Given:
Machine X is 3 times as efficient as Machine Y. Machine Y prints 1000 pages in a day.
Formula used:
[E1 × D1]/ W1 = [E2 × D2] / W2, where, E is efficiency, D is the number of days, and W id work done.
Calculation:
Let the required number of pages that can be printed by X in 2 days be ‘W”
According to the question:
3 × 2 × 1/W = 1 × 1 × 1/1000
⇒ W = 3 × 2 × 1000 = 6000 pages
∴ Machine X print 6000 in 2 days
