Correct Answer - Option 1 : 6 ∶ 1
Given:
Radius of spherical ball is one-fourth of that of cylindrical pipe.
Height of cylinder is 3 times the radius of sphere.
Concepts used:
CSA of cylinder = 2πrh
CSA of sphere = 4π(r’)2
Calculation:
Let radius of cylindrical pipe be r units.
⇒ Radius of spherical ball (r’) = r/4 units
Height of cylinder (h) = 3 × radius of spherical ball = 3 × r/4 = 3r/4
CSA of cylindrical tool = 2πrh
⇒ 2πr × 3r/4= 3πr2/2 units
CSA of spherical ball = 4π(r’)2
⇒ CSA of spherical ball = 4π × (r/4)2 = πr2/4 units
Ratio = CSA of cylindrical pipe/CSA of spherical ball
⇒ Ratio = (3πr2/2)/(πr2/4) = 6 ∶ 1
∴ Ratio of CSA of cylindrical pipe and CSA of spherical ball is 6 ∶ 1.