Correct Answer - Option 4 : 364
Given
At least multiple of 7, which leaves the remainder 4, when divided by any of 6, 9, 15 and 18 is
Concept used
Lcm method
Calculation
Lcm of (6, 9, 15, 18) is 90
It can also be the multiple of 90
Let it be k
As per the question,
⇒ \(\frac{{90k\ +\ 4}}{7}\)
We know 12 × 7 = 84
90k can be written as 84k + 6k
⇒ \( \frac{{84k\ +6k\ +\ 4}}{7}\)
⇒ 6k + 4
Let us take k = 4 for which it is completely divisible by 7
⇒ 6 × 4 + 4 = 28
Required number = 90k + 4
∴ 360 + 4 = 364.
