Correct Answer - Option 4 : Both option 1 and 2 are correct
Concept:
The roots of a quadratic equation ax2 + bx + c = 0
\(\rm x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)
- The sum of the roots = \(\rm -b\over a\)
- The product of the roots = \(\rm c\over a\)
Calculation:
Given quadratic equation:
ax2 + bx + c = 0
Roots are
Now the sum of the roots = \(\rm -b\over a\)
α + -α = \(\rm -b\over a\)
0 = \(\rm -b\over a\)
b = 0
Also product of the roots = \(\rm c\over a\)
α × -α = \(\rm c\over a\)
-α2 = \(\rm c\over a\)
c = -α2a