Correct Answer - Option 1 :
\(\frac{1}{{\sqrt 3 }}\)
Concept:
The standard equation of the ellipse is \(\frac{{{{\rm{x}}^2}}}{{{{\rm{a}}^2}}} + {\rm{\;}}\frac{{{{\rm{y}}^2}}}{{{{\rm{b}}^2}}} = 1\).
- For any ellipse the eccentricity is always less than 1.
- For any ellipse the following relation holds for:\({{\rm{b}}^2} = {{\rm{a}}^2}\left( {1 - {{\rm{e}}^2}} \right)\)
Calculation:
The given equation of the ellipse is 2x2 + 3y2 = 6.
Divide throughout by 6 to get the equation in the standard form.
\(\frac{{{{\rm{x}}^2}}}{3} + {\rm{\;}}\frac{{{{\rm{y}}^2}}}{2} = 1\)
Therefore, a2 = 3 and b2 = 2.
Now, for any ellipse using the relation we can write:
\(2 = 3\left( {1 - {{\rm{e}}^2}} \right)\)
e2 = \(\frac{1}{3}\)
e = \(\frac{1}{{\sqrt 3 }}\)
Therefore, the eccentricity of the given ellipse is \(\frac{1}{{\sqrt 3 }}\).