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The sum of the squares of sides of a right-angled triangle is 8,450 square units. What is the length of its hypotenuse?
1. 50 units
2. 55 units
3. 60 units
4. 65 units

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Correct Answer - Option 4 : 65 units

Given:

The sum of the squares of sides of a right-angled triangle is 8,450 square units.

Concept Used:

In right-angle ΔABC,

If ∠B = 90° 

Then by using pythagorus theorem,

(Hypotenuse)2 = (Pependicular)2 + (Base)2

AC2 = AB2 + BC2

Calculation:

Let the sides of the right-angled triangle be “a” and “b” units respectively.

If “h” is the length of the hypotenuse,

Then according to the concept used,

⇒ a2 + b2 = h2      ----(1)

Now, it is given that the sum of the squares of sides of a right-angled triangle is 8,450 square units.

a2 + b2 + h2 = 8450      ----(2)

Now from equation (1) and (2),

2h2 = 8450

⇒ h2 = 8450/2

⇒ h2 = 4225

⇒ h = 65.

The length of hypotenuse is 65.

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