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Find the smallest number which is when divided by 12, 16 and 18, the remainder in each case is 5.
1. 146
2. 147
3. 148
4. 149

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Correct Answer - Option 4 : 149

Calculation:

The smallest number divisible by 12, 16 and 18 = LCM of 12,16 and 18 

⇒ LCM of 12, 16 and 18 = 144

As we need remainder 5 in each case so the number = LCM + 5

⇒ 144 + 5 = 149

The smallest number which when divided by 12,16 and 18 gives remainder 5 is 149.

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