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If a number 18345mn is divisible by 9 then find the min vale of (m + n)?
1. 8
2. 6
3. 7
4. 5

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Correct Answer - Option 2 : 6

Given:

Number = 18345 mn

Concept used:

For a number to be divisible by 9 the sum of digits must be divisible by 9

Calculation:

Sum of digits = 1 + 8 + 3 + 4 + 5 + m + n 

⇒ Sum of digits = 21 + m + n 

For min value of m + n

21 + m + n = 27

∴ m + n = 6

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