LIVE Course for free

Rated by 1 million+ students
Get app now
0 votes
28 views
in Electronics by (30.0k points)
closed by
A coil with 10 Ω resistance and 2 H inductance is connected to a 50 V battery. What will be the energy stored in the coil?
1. 25 J
2. 50 J
3. 75 J
4. 100 J

1 Answer

0 votes
by (53.7k points)
selected by
 
Best answer
Correct Answer - Option 1 : 25 J

Concept:

The power stored in an inductor is given by

⇒ P = Vi      -----(1)

Where V = Voltage induced in an inductor, and i = current 

The voltage induced in the inductor is given by

\(⇒V =L\frac{dI}{dt}\)

Substituting the above equation in equation 1, it becomes 

\(⇒P = L i \frac{dI}{dt}\)

The energy stored in the inductor is given by

\(⇒E = \int P dt\)

Substituting the value of P in the above equation

\(⇒ E = \int L i\frac{dI}{dt}dt\)

\(⇒ E = \int L i di\)

\(⇒ E = \frac{1}{2} LI^{2}\)

Calculation:

R = 10 Ω, L = 2 H

I = 50 / 10 = 5 A

E = ( 2 × 52 )  / 2 

= 25 J

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...