Correct Answer - Option 1 : 25 J

__Concept:__

The power stored in an inductor is given by

⇒ P = Vi -----(1)

Where V = Voltage induced in an inductor, and i = current

The voltage induced in the inductor is given by

\(⇒V =L\frac{dI}{dt}\)

Substituting the above equation in equation 1, it becomes

\(⇒P = L i \frac{dI}{dt}\)

The energy stored in the inductor is given by

\(⇒E = \int P dt\)

Substituting the value of P in the above equation

\(⇒ E = \int L i\frac{dI}{dt}dt\)

\(⇒ E = \int L i di\)

\(⇒ E = \frac{1}{2} LI^{2}\)

**Calculation:**

R = 10 Ω, L = 2 H

I = 50 / 10 = 5 A

E = ( 2 × 5^{2} ) / 2

= **25 J**