Correct Answer - Option 1 : 25 J
Concept:
The power stored in an inductor is given by
⇒ P = Vi -----(1)
Where V = Voltage induced in an inductor, and i = current
The voltage induced in the inductor is given by
\(⇒V =L\frac{dI}{dt}\)
Substituting the above equation in equation 1, it becomes
\(⇒P = L i \frac{dI}{dt}\)
The energy stored in the inductor is given by
\(⇒E = \int P dt\)
Substituting the value of P in the above equation
\(⇒ E = \int L i\frac{dI}{dt}dt\)
\(⇒ E = \int L i di\)
\(⇒ E = \frac{1}{2} LI^{2}\)
Calculation:
R = 10 Ω, L = 2 H
I = 50 / 10 = 5 A
E = ( 2 × 52 ) / 2
= 25 J