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Suppose that in a given year, the probability that the Steelers will win their division is 1/6, the probability that the Jets will win their division is 1/12, and the probability that both will win their divisions is 1/24. What is the probability that one of the teams will win their division?

1. 5/24
2. 1/6
3. 0
4. 1/12

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Correct Answer - Option 1 : 5/24


  • For two events A and B, we have: P(A ∪ B) = P(A) + P(B) - P(A ∩ B).


Given: P(Steelers will win) = 1/6, P(Jet will win) = 1/12 and P(Steelers and jets will win) = 1/24

P(One will win) = P(Steelers or jets will win)

P(One will win) = P(Steelers will win) + P(Jet will win) - P(Steelers and jets will win)

P(One will win) = (1/6) + (1/12) - (1/24)

P(One will win) = 5/24

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