Correct Answer - Option 3 : 2

**Given:**

\(\frac{log128-log8}{log4}\)

**Formula used:**

If base is same

Log a - Log b = Log(a/b)

Log(a^{n}) = n Log a

**Calculation:**

According to the question,

(Log 128 - Log 8)/Log 4

Using the log formula

⇒ Log(128/8)/Log 4

⇒ Log 16/Log 4

⇒ Log(4^{2})/Log 4

Using the formula Log(an) = n Log a

⇒ 2 Log 4/Log 4

⇒ 2

**∴ The value of \(\frac{log128-log8}{log4}\) is 2.**