Correct Answer - Option 3 : 2
Given:
\(\frac{log128-log8}{log4}\)
Formula used:
If base is same
Log a - Log b = Log(a/b)
Log(an) = n Log a
Calculation:
According to the question,
(Log 128 - Log 8)/Log 4
Using the log formula
⇒ Log(128/8)/Log 4
⇒ Log 16/Log 4
⇒ Log(42)/Log 4
Using the formula Log(an) = n Log a
⇒ 2 Log 4/Log 4
⇒ 2
∴ The value of \(\frac{log128-log8}{log4}\) is 2.