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Two cyclists A and B travel from city X to city Y, at speed of 60 km/h and 48 km/h. If the cyclists A takes 2 hours lesser time than cyclists B for the journey, then what is the distance between the two cities ?
1. 400 km
2. 480 km
3. 220 km
4. 160 km

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Correct Answer - Option 2 : 480 km

Given:

Speed of cyclist A is  60 km/h.

Speed of cyclist B is 48 km/h.

cyclists A takes 2 hours lesser time than cyclists B  for the journey.

Concept Used:

If the distance covered by two persons is equal, then the time taken by them for the journey is inversely proportional to their speed.

Calculation:

The ratio of the speed of A and B is 60 : 48 = 5 : 4

Since the distance covered by them is equal, the ratio of time taken by A : B = 4 : 5

The difference in the ratio of time taken by them = (5 - 4) unit = 1 unit

Now, according to the question 

1 unit = 2 hours.

⇒ 4 units = 8 hours.

Time taken by A to cover the distance from city X to city Y = 8 hours.

Distance = 60 km/h × 8 hour = 480 km.

∴ Distance between two cities X and Y is 480 km.

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