Question

The minimum transverse reinforcement is prestressed concrete beam is given by formula
1. \(\frac{{{S_v}}}{{bA_{s_v}}} = \frac{{0.87\;{f_y}}}{{0.4}}\)
2. \(\frac{{{A_{{s_v}}}}}{{b{S_v}}} = \frac{{0.4}}{{0.87\;{f_y}}}\)
3. \(\frac{{{A_{{s_v}}}}}{{0.87\;{f_y}}} = \frac{{0.4}}{{b{S_v}}}\)
4. \(\frac{{b{S_v}}}{{0.4\;}} = \frac{{{A_{{s_v}}}}}{{0.87{f_y}}}\)

Answer 1

Correct Answer - Option 2 : \(\frac{{{A_{{s_v}}}}}{{b{S_v}}} = \frac{{0.4}}{{0.87\;{f_y}}}\)

Concept:

Minimum transverse reinforcement is provided in the form of stirrups

According to clause 22.4.3.1 of IS 1343 - 1980

\(\frac{{{{\rm{A}}_{{\rm{sv}}}}}}{{{\rm{b}} \;\times\; {{\rm{s}}_{\rm{v}}}}} = \frac{{0.4}}{{0.87\; \times\; {{\rm{f}}_{\rm{y}}}}}\)

A_sv – total cross-sectional area of stirrup legs effective in shear

s_v – stirrup spacing along the Length of the member.

b – breadth of the member which for T, I and L beams should be taken as the breadth of ribs b_w

f_y – characteristic strength of stirrup reinforcement in N/mm² which shall not be taken greater than 415 N/mm²