Correct Answer - Option 2 : 5
Given:
If 2nC3 : nC2 = 12 : 1
Formula used :
nCr = n!/r!(n - r)!
Calculation:
If 2nC3 : nC2 = 12 : 1 ----(1)
Using the formula
2nC2 = {2n!/3! (2n - 3)!}
⇒ 2n(2n - 1)(2n - 2)(2n - 3)!/(2n - 3)! × 3 × 2
⇒ n(2n - 1)2(n - 1)/3 ----(2)
nC2 = {n!/2! (n - 2)!
⇒ n(n - 1)(n - 2)!/(n - 2)! × 2
⇒ n(n - 1)/2 ----(3)
Putting equation 2 and 3 in equation 1
⇒ {n(2n - 1)2(n - 1)/3}/{n(n - 1)/2} = 12/1
⇒ 2n - 1 = 9
⇒ 2n = 10
⇒ n = 5
∴ The value of n is 5.