Correct Answer - Option 2 :
\(Y_d = \dfrac{Y}{1+w}\)
Concept:
Water Content ( W ):
It is defined as the ratio of the weight of water to the weight of solid in a given soil mass. It is usually expressed as a percentage.
\(w = \;\frac{{{W_W}}}{{{W_S}}} \times 100 = \;\frac{{W - {W_S}}}{{{W_S}}} \times 100\)
Bulk density:
It is defined as the ratio of the total mass ( M ) of the soil to the total volume ( V ) of the soil. It is expressed in Kg / m3
\(\rho = \;\frac{M}{V}\)
Dry density:
It is defined as the ratio of the mass of Solids to the total Volume of the soil ( in moist condition ).
\({\rho _d} = \;\frac{{{M_S}}}{V}\)
Relation between dry unit weight, bulk unit weight, and water content ( w ).
We know that,
\(w = \frac{{{W_W}}}{{{W_S}}}\)
\(w + 1 = \;\frac{{{W_W}}}{{{W_S} + 1}}\) =\(\frac{{{W_{W + {W_S}}}}}{W}\)
\(w + 1 = \;\frac{W}{{{W_S}}}\)
\({W_S} = \;\frac{W}{{1 + w}}\)
Dividing both sides by V, we get
\(\frac{W_s}{V} = \frac{W}{V(1+w)}\)
\({\gamma _{d\;}} = \;\frac{\gamma }{{1 + w}}\;\)