Correct Answer - Option 1 : 6 m
Concept:
Displacement: The net change in position is called displacement.
Velocity: It the rate of change of displacement.
\(v = \frac{dx}{dt}\)
Writing this equation in another way.
dx = v.dt
And if do integration both side, we will get
\(\int dx =\int_{t_1}^{t_2} v.dt\)
Calculation:
Given velocity v = 2t - 5
So, the displacement from t = 0 to t = 3 second is given as
\(x =\int_{0}^{3} (2t -5).dt\)
⇒ \(x = \left [ 2\frac{t^2}{2} \right ]_{0}^{3} - \left [ 5t \right ]_{0}^{3}\)
⇒ x = 3 2 - 5 × 3 = - 6 m
So, displacement is - 6 m
The magnitude of displacement is 6 m.