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Find the number of certain first consecutive natural numbers whose average is 10.5.
1. 25
2. 20
3. 18
4. 22

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Correct Answer - Option 2 : 20

Given:

Average of certain first consecutive natural numbers is 10.5

Formula used:

Average = Sum of observations / Number of observations

Average of ‘first’ “n” natural numbers = [(n + 1)/2]th term      [When number of terms are odd]

Average of ‘first’ “n” natural numbers = Average of the two middle terms = [(n/2)th term + (n/2 + 1)th term] / 2      [When number of terms are even]

Calculation:

As the terms are consecutive so the middle term cannot be 10.5 as they are natural numbers hence the number of terms are even.

Let the middle terms be x and x + 1

⇒ Average of middle terms = (2x + 1)/2

⇒ (2x + 1)/2 = 10.5

⇒ x = 20/2 = 10

Middle terns are 10 and 11

There are 9 terms before 10, so there will be 9 terms after 11

Hence number of terms = 11 + 9 = 20

∴ Number of certain first consecutive natural numbers whose average is 10.5 is 20

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