# In the given question, two equations numbered l and II are given. Solve both the equations and mark the appropriate answer. I. ${x^2} - 14x + 48 = 0\ 0 votes 11 views in Aptitude closed In the given question, two equations numbered l and II are given. Solve both the equations and mark the appropriate answer. I. \({x^2} - 14x + 48 = 0$

II. ${y^2} - 16y + 63 = 0$

1. x > y
2. x < y
3.

x ≥ y

4.

x ≤ y

5.

x = y or relationship between x and y cannot be established

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Correct Answer - Option 5 :

x = y or relationship between x and y cannot be established

I.${x^2} - 14x + 48 = 0$

$⇒ {x^2} - 6x - 8x + 48 = 0$

$⇒ x\left( {x - 6} \right) - 8\left( {x - 6} \right) = 0$

$⇒ \left( {x - 6} \right)\left( {x - 8} \right) = 0$

⇒ x = 6  or 8

II. ${y^2} - 16y + 63 = 0$

$⇒ {y^2} - 9y - 7y + 63 = 0$

$⇒ y\left( {y - 9} \right) - 7\left( {y - 9} \right) = 0$

$⇒ \left( {y - 7} \right)\left( {y - 9} \right) = 0$

⇒ y = 7  or 9

Comparison between x and y (via Tabulation):

 Value of x Value of y Relation 6 7 x < y 6 9 x < y 8 7 x > y 8 9 x < y

∴ x = y or relationship between x and y cannot be established