LIVE Course for free

Rated by 1 million+ students
Get app now
0 votes
9 views
in Aptitude by (30.0k points)
closed by

In the given question, two equations numbered l and II are given. Solve both the equations and mark the appropriate answer.

I. \({x^2} - 22x + 117 = 0\)

II. \({y^2} + 4y - 96 = 0\)


1. x > y
2. x < y
3. x ≥ y
4. x ≤ y
5. x = y or relationship between x and y cannot be established

1 Answer

0 votes
by (54.3k points)
selected by
 
Best answer
Correct Answer - Option 1 : x > y

I. \({x^2} - 22x + 117 = 0\)

\( \Rightarrow {x^2} - 13x - 9x + 117 = 0\)

\( \Rightarrow x\left( {x - 13} \right) - 9\left( {x - 13} \right) = 0\)

\( \Rightarrow \left( {x - 13} \right)\left( {x - 9} \right) = 0\)

\( \Rightarrow x = 9\) or 13

 

II. \({y^2} + 4y - 96 = 0\)

\( \Rightarrow {y^2} + 12y - 8y - 96 = 0\)

\( \Rightarrow y\left( {y + 12} \right) - 8\left( {y + 12} \right) = 0\)

\( \Rightarrow \left( {y - 8} \right)\left( {y + 12} \right) = 0\)

\( \Rightarrow y = - 12\) or 8

Comparison between x and y (via Tabulation):

Value of x

Value of y

Relation

9

-12

x > y

9

8

x > y

13

-12

x > y

13

8

x > y


∴ Clearly x > y

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...