Correct Answer  Option 5 : x = y or relationship between x and y cannot be established
Calculation:
I. 15x2 – 29x – 14 = 0
⇒ 15x^{2} – 35x + 6x – 14 = 0
⇒ 5x(3x – 7) + 2(3x – 7) = 0
⇒ (5x + 2) (3x – 7) = 0
⇒ x = 2/5 or 7/3
II. 6y2 – 5y – 25 = 0
⇒ 6y^{2} – 15y + 10y – 25 = 0
⇒ 3y(2y – 5) + 5(2y – 5) = 0
⇒ (3y + 5) (2y – 5) = 0
⇒ y = 5/3 or 5/2
Value of x

Value of y

Relation

2/5

5/2

x < y

2/5

5/3

x > y

7/3

5/2

x > y

7/3

5/3

x > y

∴ Relationship between x and y cannot be established