Correct Answer - Option 1 : a

^{x }log

_{e}a

**Concept:**

Some useful formulas are:

\(\rm d(a^x) \over dx\)= ax logea

**Calculation:**

In the given problem direct formulae can be used, which gives,

\(\rm d(a^x) \over dx\)= ax logea

So, the correct option is (1)