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There are two planets A and B in the solar system. The acceleration due to gravity on planet A is 11 times the acceleration due to gravity on planet B. If a man jumps to a height of 3 m on planet A, what is the height of jump by the same person on planet B?

1. 4 m
2. 12 m
3. 27 m
4. 33 m

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Correct Answer - Option 4 : 33 m

The correct answer is option 4) i.e. 33 m


Kinematic equations of motion:

  • These equations define the relationship between initial velocity u, final velocity v, time t, and displacement s of an object with respect to its motion in uniform acceleration a.
  • Following are the three kinematic equations for uniformly accelerated motion:

⇒ v = u + at

⇒ s = ut + 0.5at2

⇒ v2 - u2 = 2as


Given that:

gA =11gB      ----(1)

Height of jump on planet A, hA = 3 m

Height of jump on planet b = hB

Using the equation of kinematics, v2 - u2 = 2gh

When the man jumps, his final velocity v = 0, and the acceleration due to gravity is negative.

⇒ - u2 = 2(-g)h

\(⇒ g = \frac{u^2}{2h}\)

Therefore, \(g_A = \frac{u^2}{2h_A}\) and \(g_B = \frac{u^2}{2h_B}\)      ----(2)

From (1) and (2),

\(\Rightarrow \frac{u^2}{2h_A} = 11\frac{u^2}{2h_B}\)

\(\Rightarrow h_B = 11h_A = 11 \times 3 = 33\: m\)

The height of the jump by the same person on planet B is 33 m.

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