Correct Answer - Option 3 : x ≥ y
Calculation:
I. x2 + 8x + 15 = 0
⇒ x2 + 3x + 5x+ 15 = 0
⇒ x(x + 3) + 5(x + 3) = 0
⇒ (x + 3) (x + 5) = 0
∴ x = -3, -5
II. y2 + 12y + 35 = 0
⇒ y2 + 5x + 7x + 35 = 0
⇒ y(y + 5) + 7(x + 5) = 0
⇒ (y + 5) (y + 7) = 0
∴ y = -5, -7
Comparison between x and y (via Tabulation):
Value of x
|
Value of y
|
Relation
|
-3
|
-5
|
x > y
|
-3
|
-7
|
x > y
|
-5
|
-5
|
x = y
|
-5
|
-7
|
x > y
|
∴x ≥ y