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Two bodies start from opposite ends P & Q at the same time and move towards each other with speeds 3 m/s and 5 m/s. After meeting each other, P takes 25 seconds how much time does Q take to reach their destinations in seconds? 


1. 9
2. 11
3. 16
4. 25

1 Answer

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Best answer
Correct Answer - Option 1 : 9

Given:

S(P) = 3 m/s,

S(Q) = 5 m/s

Formula Used:

Speed = Distance/ Time

Calculation:

Let us assume that the two bodies meet at a point R, after time T.

⇒ For the P, PR = S1(T) and RQ = S1(T1)

⇒ For the Q, QR = S2T and RP = S2(T2)

PR = RP & QR = RQ

⇒ S1(T) = S2(T2)

⇒ S2(T) = S1(T1)

Dividing the above two equations, we will get S1(T)/S2(T) = S2(T2)/S1(T1)

⇒ S1/S2 = √t2/√t1

⇒ √t2 = √t1 × (S1/S2)

⇒ √t2 = √25 × (3/5)

⇒ √t2 = 5 × 3/5

⇒ t2 = 9 seconds

∴ Q takes 9 seconds to reach the destination.

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