Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
259 views
in Statistics by (115k points)
closed by
For a histogram based on a frequency distribution with unequal class intervals, the frequency of a class should be proportional to:
1. the height of the rectangle.
2. the area of the rectangle.
3. the width of the rectangle.
4. the perimeter of the rectangle.

1 Answer

0 votes
by (114k points)
selected by
 
Best answer
Correct Answer - Option 2 : the area of the rectangle.

Concept:

  • When constructing a histogram with non-uniform (unequal) class widths, we must ensure that the areas of the rectangles are proportional to the class frequencies.
  • Remember that the histogram differs from a bar chart in that it is the area of the bar that denotes the value, not the height. This means that we would need to consider the widths in order to determine the height of each rectangle.

 

Calculation:

From the definition of histogram, it is clear that the frequency of a class is proportional to the area of the rectangle, and NOT to its height.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...