Correct Answer - Option 1 : 4πε
0r
Concept:
By Gauss law, \(ϵ \oint \vec{E}.d\vec{s}={{Q}_{encl}}\)
Thus, \(ϵ \oint \vec{E}.d\vec{s}={{ϵ }_{0}}E\left( 4π {{r}^{2}} \right)\)
\(ϕ = \oint \vec{E}.d\vec{s}\)
where ϕ = flux coming out of the concentric sphere.
r = radius of the sphere
Calculation:
Since electric potential can be defined as:
\(V = \frac{Q}{{4πϵ{_0}r}}\)
V = 1 V (given)
Q = 4 π ϵ0 r
\(ϕ =ϵ \oint \vec{E}.d\vec{s}={4\pi\epsilon_0r}\)