Correct Answer - Option 4 : None of these
Concept:
- Law of Mass action and Equilibrium constant:
- At a constant temperature, the rate of a chemical reaction is directly proportional to the product of molar concentrations of reactants present at any given time. This is the law of mass action.
-
The equilibrium constant for the reversible reaction of type \(aA + bB \rightleftharpoons cC + dD\) is represented as
\({K_{\rm{c}}}{\rm{ = }}\frac{{{{{\rm{[C]}}}^{\rm{c}}}{{{\rm{[D]}}}^{\rm{d}}}}}{{{{{\rm{[A]}}}^{\rm{a}}}{{{\rm{[B]}}}^{\rm{b}}}}}\)
Characteristics of an equilibrium constant:
- It is a definite value for all chemical reactions.
-
The constants Kp and Kc are both equilibrium constants.
-
Kp is used when the concentration terms are given in partial pressures i.e, in gaseous reactions.
-
Kc is used when the reaction terms are expressed in molarities.
- The relation between Kp and Kc is given by:
\({K_p} = {K_c} × {\left( {RT} \right)^{\Delta n}}\) where R = Universal gas constant, T = Temperature, and \(\triangle n\) = change in moles of gases in the reaction.
Calculation:
- The equation is: H2 + I2 = 2HI
- The equilibrium constant for the above reaction is:
\(K_C = {[HI]^2 \over [H_2][I_2]}\) where [HI], [H2], [I2] are the concentration of the reactants and products expressed in moles/litre or mol litre-1.
- Putting the dimension of the concentration units, in the above equation, we get:
\(K_c = {({mol-litre^{-1}})^2\over (mol-litre^{-1})(mol -litre^{-1})}\)
or, Kc = 1.
- Hence, the equilibrium constant has no dimension, or it is a dimensionless quantity.
Hence, the correct option is none of the above.