Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
163 views
in Electronics by (115k points)
closed by
For the signal f(t) = 2 sin 9πt + sin 12 πt + sin 14 πt the minimum sampling frequency (in Hz) satisfying the Nyquist criterion is:
1. 14 sample / sec
2. 8 sample / sec
3. 12 sample / sec
4. None of the above

1 Answer

0 votes
by (114k points)
selected by
 
Best answer
Correct Answer - Option 1 : 14 sample / sec

Nyquist Sampling Theorem:

A continuous-time signal can be represented in its samples and can be recovered back when sampling frequency fs is greater than or equal to twice the highest frequency component of the message signal, i.e.

fs  ≥ 2 fm

Where,

fs is the sampling frequency

fm is the highest frequency component of the message signal

Therefore to convert continuous signals to discrete signals, the sampling must be done at the Nyquist rate.

Calculation:

Given: f(t) = 2 sin 9πt + sin 12 πt + sin 14 πt, 

ωm = 14π rad/sec

fm = 14π/2π = 7 Hz

For getting minimum sampling frequency,

fs = 2 fm

= 2 × 7 

= 14 Hz

= 14 samples/sec

Therefore, The minimum sampling frequency is 14 Hz

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...