Correct Answer - Option 1 : 1
Concept:
Iota power:
- i2 = -1, i3 = -i, i4 = 1
- Number of the form 2n is always even, n ∈ N
- Numebr of the form 2n +1 or 2n - 1 is always odd, n ∈ N
- (-a)2n -1 = -(a)2n -1
Calculation:
Given:
i2n + 1(-i)2n - 1
From the concept used we know that 2n - 1 is odd
⇒ i2n + 1(-i)2n - 1
⇒ - (i)2n + 1(i)2n - 1
⇒ - (i)2n + 1 + 2n - 1
⇒ - (i)4n
⇒ - (i4)n
⇒ - (1)n = -1
Hence, the modulus of the complex number i2n + 1(-i)2n - 1 is 1.