Correct Answer - Option 1 :
\(6\frac{2}{3}\)%
Given:
Initially, total volume of drink is 50 liters.
Calculations:
Volume of pure sugar,
⇒ 8% of 50 = (8/100) × 50 = 4 liters.
Now, given that, 10 liters of water is added then,
⇒ Total mixture = 50 + 10 = 60 liters
Volume of pure sugar is still 4 liters
⇒ % volume of sugar = (volume of sugar × 100)/(Total mixture)
⇒ (4 × 100)/60
⇒ \(6\frac{2}{3}\)%
∴ The percentage of sugar in the new drink is \(6\frac{2}{3}\)%