# Find the mid-point of the line joining the points P(3, - 1, 2) and Q(3, 3, - 2)?

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Find the mid-point of the line joining the points P(3, - 1, 2) and Q(3, 3, - 2)?
1. (3, 2, 0)
2. (- 3, 1, 0)
3. (3, 1, 0)
4. (3, 1, 4)

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Correct Answer - Option 3 : (3, 1, 0)

Concept:

Let A(x1, y1, z1) and B(x2, y2, z2) be two points on a 3D plane then mid-point of the line joining the points A and B is given by: $\rm (\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}, \frac{z_{1}+z_{2}}{2}).$

Calculation:

Given: P(3, - 1, 2) and Q(3, 3, - 2) are two points on a 3D plane.

As we know that, the mid-point of the line joining the points A(x1, y1, z1) and B(x2, y2, z2) is given by: $\rm (\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}, \frac{z_{1}+z_{2}}{2}).$

Let the mid-point of the line joining the points P(3, - 1, 2) and Q(3, 3, - 2) be R.

$\Rightarrow \rm R=(\frac{3+3}{2}, \frac{-1+3}{2} ,\frac{2-2}{2} )=(3, 1, 0)$

Hence, the correct option is 3.