# Find the distance between the points A(1, 2, 5) and B(3, - 1, 0)?

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Find the distance between the points A(1, 2, 5) and B(3, - 1, 0)?
1. $\sqrt{38}$
2. $\sqrt{48}$
3. 3
4. 8

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Correct Answer - Option 1 : $\sqrt{38}$

Concept:

Let A(x1, y1, z1) and B(x2, y2, z2) be two point on a 3D plane then the distance between the points A and B is given by:$\rm \sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}+(z_{2}-z_{1})^{2}}$

Calculation:

Given: A(1, 2, 5) and B(3, - 1, 0) are two points in a 3D plane.

As we know that, the distance between the points A(x1, y1, z1) and B(x2, y2, z2) is given by: $\rm \sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}+(z_{2}-z_{1})^{2}}$

Let d be the distance between the points A and B.

$\Rightarrow \rm d=\sqrt{(3-1)^{2}+(-1-2)^{2}+(0-5)^{2}}=\sqrt{4+9+25}=\sqrt{38}$

Hence, the correct option is 1.