Question

The smallest number of 4 digits which when divided by 6, 8, 12 and 20 leaves a remainder 5 in each case is :
1. 1285
2. 1200
3. 1085
4. 1080

Answer 1

Correct Answer - Option 3 : 1085

Concept Used 

We need to find the LCM of the given number 

Calculation 

LCM of (6, 8, 12, 20) = 120 

Now, find the smallest four-digit no. which is divisible by 120 

So, 1080 is divisible by 120 

Required number = 1080 + 5 = 1085 

∴ The smallest number of 4 digits which when divided by 6, 8, 12, and 20 leaves a remainder 5 in each case is 1085