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If cosec θ - sin θ = p3 and sec θ - cos θ = q3, then what is the value of tan θ ?
1. \(\dfrac{p}{q}\)
2. \(\dfrac{q}{p}\)
3. pq
4. p2q2

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Best answer
Correct Answer - Option 2 : \(\dfrac{q}{p}\)

Given :

cosec θ - sin θ = p3 and sec θ - cos θ = q3

Concept used :

1 - sin2 θ = cos2 θ 

1 - cos2 θ = sin2 θ 

Calculations :

cosec θ - sin θ = 1/(sin θ) - sin θ 

⇒ (1 - sin2 θ)/sin θ 

⇒  (cos2 θ)/(sin θ)

So, 

(cos2 θ)/(sin θ) = p3      ....(1) 

Now 

sec θ - cos θ = (1/cos θ) - cos θ 

⇒ (1 - cos2 θ)/cos θ 

⇒  (sin2 θ)/(cos θ)

So, 

(sin2 θ)/(cos θ) = q3      ....(2) 

Divide equation (2) by (1) 

(sin2 θ)/(cos θ) ÷ (cos2 θ)/(sin θ) = q3/p3 

⇒ sin3 θ/cos3 θ = q3/p3 

⇒ tan θ = q/p 

∴ Option 2 is the correct answer.

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