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In a 1 km race, A gives B a start of 120 m and C a start of 160 m. They all finish the race together. How much start can B give to C in order to finish the same race together?
1. \(55 \frac 4 {11} \) m
2. \(48 \frac 6 {11} \) m
3. \(45 \frac 5 {11} \) m
4. \(47 \frac 2 {11} \) m

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Correct Answer - Option 3 : \(45 \frac 5 {11} \) m

Given:

Total length of race = 1000 m

A gives B a start of = 120 m

A gives C a start of = 160 m

Concept:

If they start the race together, then B and C would be 120 m and 160 m behind A when A finishes the race.

Calculation:

The ratio of distance covered by A, B, and C if they start the race together when A finishes the race 

= 1000 ∶ 880 ∶ 840

∴ In a 880 m race;

B can give a start of 40 m to C.

880 m race C gets start = 40 m

1 m race C gets a start = 40/880 m

1000 m race C gets a start = (40/880) × 1000

\(45 \frac 5 {11} \) m

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