Question

Two students appeared for an examination. One of them secured 9 marks more than the other and his marks were 56 % of the sum of their marks. The marks obtained by them are-

1. 30 and 39
2. 36 and 45
3. 33 and 42
4. 35 and 44
5. None of these

Answer 1

Correct Answer - Option 3 : 33 and 42

Formula Used 

Percentage = Actual/Total × 100

Calculation 

Let the marks obtained by first student = a

Then marks obtained by second student = a + 9

According to the question,

⇒ a + 9 = ( a + a + 9 ) × 56 %

⇒ 12a = 396

⇒ a = 33

Marks of the first student = 33

Marks of second student = 33 + 9 = 42

∴ The Required answer is 33 and 42