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Monthly savings of A is Rs. 6000 more than that of B. Monthly salaries of A and B are in the ratio 16 : 11. Find the average monthly salary of both of them together, if the monthly expenditure of A is one-third more than the expenditure of B and A saves Rs. 12000 in a month.
1. Rs. 39000
2. Rs. 39500
3. Rs. 40000
4. Rs. 40500
5. Rs. 41000

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Correct Answer - Option 4 : Rs. 40500

Given:

Salary ratio = 16 : 11

A's expenditure = 4/3 of B's expenditure

A's savings = 6000 + B's savings

A's savings = Rs. 12000

Calculation:

Let expenditure of B be Rs. x

A's expenditure = 4x/3 

B's savings = 12000 - 6000 = 6000

A.T.Q

(4x/3 + 12000)/(x + 6000) = 16/11

⇒ 44x/3 + 132000 = 16x + 96000

⇒ 4x/3 = 36000

⇒ x = Rs. 27000

B's salary = 27000 + 6000 = 33000

A's salary = 4/3 × 27000 + 12000 = Rs. 48000

Average salary = (33000 + 48000)/2 = Rs. 40500

∴ The average salary is Rs. 40500

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