Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
154 views
in Aptitude by (115k points)
closed by
Three types of sugar are mixed together. Their volumes are in the ratio 3 : 5 : 7 and the weight of equal volumes is in the ratio 4 : 2 : 3. What is the weight of the sugar of the first type if the weight of the mixture is 387 kg?
1. 120 kg
2. 108 kg
3. 132 kg
4. 96 kg
5. 144 kg

1 Answer

0 votes
by (114k points)
selected by
 
Best answer
Correct Answer - Option 2 : 108 kg

Given:

Volume ratio = 3 : 5 : 7

Weight ratio of equal volume = 4 : 2 : 3

Total mixture = 387 kg

Calculation:

Weight ratio = (3 × 4) : (5 × 2) : (7 × 3)

⇒ 12 : 10 : 21

Total weight = 43 ratio

Required weight = 387/43 × 12 = 108 kg

∴ The answer is 108 kg

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...