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The two Watt meters A and B, give readings as 500 Watts and 1000 Watts respectively during the power measurement of 3-phase, 3-wire system. Calculate the total power of the circuit.
1. 1500 W
2. 3000 W
3. 750 W
4. 1000 W

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Best answer
Correct Answer - Option 1 : 1500 W

Blondel’s Theorem:

  • According to Blondel’s theorem, the number of watt-meters to be required to measure the total power in n-phase system is either N or (N - 1).
  • When the separate neutral wire is available in the system the no. of watt meters to be required is N.
  • When the neutral wire is not available in the system, then the no. of watt meters to be required is (N - 1). One line is acting as a common line for the return path.
  • The total power is the sum of all wattmeter readings.
     

Application:

Given reading of wattmeter A (WA) = 500 W

Reading of wattmeter B (WB) = 1000 W

According to Blondel’s theorem, the total power of the circuit (W) will be,

W = WA + WB

W = 500 + 1000 = 1500 W

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