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A 220-V, 50-Hz, 6-pole, single-phase induction motor runs with 3% slip. Determine the rotor speed.
1. 1455 rpm
2. 728 rpm
3. 970 rpm
4. 960 rpm

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Correct Answer - Option 3 : 970 rpm

Slip of Induction Motor (S):

Slip in Induction Motor is the relative speed between the rotating magnetic flux and rotor expressed in terms of per unit synchronous speed.

If Ns and Nr being the synchronous speed of rotating magnetic flux and rotor speed respectively, then the relative speed between them is equal to (Ns – Nr).

Therefore, slip is defined as

\(s=\frac{N_s-N_r}{N_s}\)

Where,

\(N_s=\frac{120f}{P}\)

f is the frequency in Hz and P is the number of poles

Application:

Given,

f = 50 Hz

P = 6

s = 3% = 0.03

\(\therefore N_s=\frac{120f}{P}=\frac{120×50}{6}=1000\ rpm\)

from above concept,

\(0.03=\frac{1000-N_r}{1000}\)

or, 1000 × 0.03 = 1000 - Nr

Nr = 970 rpm

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