Correct Answer - Option 2 : 5/13

__Concept:__

The distance between two parallel lines ax + by + c_{1} = 0 and ax + by + c_{2} = 0 is given by the formula: \(\rm d=\dfrac{|c_1-c_2|}{\sqrt{a^2+b^2}}\).

__Calculation:__

Using the concept above, we have a = 5, b = -12, c_{1} = 2 and c_{2} = -3.

∴ \(\rm d=\dfrac{|c_1-c_2|}{\sqrt{a^2+b^2}}\)

= \(\rm \dfrac{|2-(-3)|}{\sqrt{5^2+(-12)^2}}\)

= \(\rm \dfrac{|5|}{\sqrt{169}}\)

= \(\dfrac{5}{13}\).