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Which least number when divided by 12, 15, 20 and 44 leaves the remainder 6 in each case. find the number
1. 666
2. 788
3. 456
4. 660

1 Answer

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Best answer
Correct Answer - Option 1 : 666

Formula / Concept used

LCM of the above mentioned numbers would give us the least number which will be divisible by all of them

Calculation 

Adding 6 will leave 6 as remainder in each case.

⇒ 12 = 3 × 2 × 2 

⇒ 15 = 3 × 5 

⇒ 20 = 4 × 5 

⇒ 44 = 11 × 4 

⇒ LCM of 12,15, 20 and 44 = 660

⇒ Required number = 660 + 6 = 666

∴ Required number = 666

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