# When 425 is added to 6A7, the summation we get 10C2 , the number is completely divisible by 3. Calculate highest possible value of A.

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When 425 is added to 6A7, the summation we get 10C2 , the number  is completely divisible by 3. Calculate highest possible value of A.
1. 7
2. 9
3. 6
4. 5

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Correct Answer - Option 3 : 6

Given

6A7 + 425 = 10C2

10C2 is divisible by 3

Formula used

Divisibility rule of 3 = sum of all the digits are completely divisible by 3

Calculation

⇒  6A7

⇒ +425

⇒ 10C2

⇒ Where, A = 3, 6 and C = 6, 9

⇒ 10C2 is completely divisible by 3.

⇒ 10 + C + 2 is multiple of 3

⇒ C = 6, 9

∴ 6 is required value of A.