Any positive integer ending with the digit zero is divisible by 5 and so its prime factorisations must contain the prime 5.
6n = (2 × 3)n = 2n × 3n
=> The prime in the factorisation of 6n is 2 and 3.
=> 5 does not occur in the prime factorisation of 6n for any n.
=> 6n does not end with the digit zero for any natural number n.