Correct Answer - Option 1 : 48, 24, 96
Given :
Three number are such that first is twice the second and is half of the third.
If the average of three numbers is 56, the three numbers in order are = ?
Calculation :
Let the 2nd number be x.
Since the first number is twice the second, it is 2x
Since the 1st number is half of the 3rd , i.e., the 3rd number is twice the 1st,
The 3rd number is 4x.
The average of the three numbers is 56, so
(2x + x + 4x)/ 3 = 56
⇒ 7x = 56 × 3
⇒ x = 56 × 3 / 7
⇒ x = 8 × 3
⇒ x = 24
Now the difference between the 1st and the 3rd numbers is 4x - 2x
⇒ 2x
⇒ 2 × 24
⇒ 48
∴ The three numbers in order are = 48, 24, 96