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Wetted perimeter of a regime channel for a discharge of 64 cumecs as per Lacey's theory will be-
1. 38 m
2. 57 m
3. 76 m
4. 19 m

1 Answer

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Best answer
Correct Answer - Option 1 : 38 m

Explanation:

According to Lacey's theory, following formulae has been given below:

  1. Hydraulic mean depth, \(R = \frac{5}{2}\frac{{{V^2}}}{f}\)
  2. Area of the channel section, \(A = \frac{Q}{V}\)
  3. Wetted perimeter, \(P = 4.75\sqrt Q \)
  4. Regime mean velocity, \(V = {\left( {\frac{{Q{f^2}}}{{140}}} \right)^{1/6}}\)
  5. Bed Slope, \(S = \frac{{{f^{5/3}}}}{{3340{Q^{1/6}}}}\)


Calculation:

\(P = 4.75\sqrt Q =4.75\sqrt 64 = 38 \;m\)

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