Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
51 views
in Aptitude by (114k points)
closed by

The difference between the sides at a right angle in a right-angled triangle is 14 cm. The area of the triangle is 120 cm2, The perimeter of the triangle is -


1. 68 cm
2. 64 cm
3. 60 cm
4. 58 cm

1 Answer

0 votes
by (115k points)
selected by
 
Best answer
Correct Answer - Option 3 : 60 cm

Given:

The difference between the sides at a right angle in a right-angled triangle is 14 cm.

The area of the triangle is 120 cm2.

Formula Used:

Perimeter = Sum of all sides

Area of right-angled triangle = 1/2 × Base × Height

Calculation:

Let the base of the triangle be x.

Then the height of the triangle = x + 14

The area of the triangle is 120 cm2.

⇒ 1/2 × x × (x + 14) = 120

⇒ x2 + 14x = 240

⇒ x2 + 14x - 240 = 0

⇒ x = - 24, 10

Base of the triangle = 10 cm

Height of the triangle = 24 cm

By Pythagoras theorem,

Hypotenuse = √242 + 102 = √576 + 100 = 26 cm

Perimeter = 24 + 10 + 26 = 60 cm

∴ The perimeter of the triangle is 60 cm.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...