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A 500-watt carrier is modulated to a depth of 80%. Calculate the total power in the modulated wave.
1. 512.5 W
2. 500 W
3.  450 W
4. 660 W

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Correct Answer - Option 4 : 660 W

Concept:

The total transmitted power for an AM system is given by:

\({P_t} = {P_c}\left( {1 + \frac{{{μ^2}}}{2}} \right)\)

Pc = Carrier Power

μ = Modulation Index

Calculation:

With PC = 500 W and μ = 0.80, the total power in the modulated wave will be:

\({P_t} = {500}\left( {1 + \frac{{{(0.8)^2}}}{2}} \right)\)

Pt = 660 W

NoteThe transmitted power is independent of the modulation index in the case of FM and PM.

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