Correct Answer - Option 4 : 660 W
Concept:
The total transmitted power for an AM system is given by:
\({P_t} = {P_c}\left( {1 + \frac{{{μ^2}}}{2}} \right)\)
Pc = Carrier Power
μ = Modulation Index
Calculation:
With PC = 500 W and μ = 0.80, the total power in the modulated wave will be:
\({P_t} = {500}\left( {1 + \frac{{{(0.8)^2}}}{2}} \right)\)
Pt = 660 W
Note: The transmitted power is independent of the modulation index in the case of FM and PM.